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(1/4)^3x^2+1=128^x
We move all terms to the left:
(1/4)^3x^2+1-(128^x)=0
Domain of the equation: 4)^3x^2!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/4)^3x^2-128^x+1=0
We multiply all the terms by the denominator
(+1-128^x*4)^3x^2+1*4)^3x^2=0
Wy multiply elements
(+1-128^x*4)^3x^2+4x=0
We add all the numbers together, and all the variables
4x+(+1-128^x*4)^3x^2=0
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